<egg|zzz|egg>
ping me in kspacademia when I'm there if you want, I'm on that channel at work
<Greys>
if you roll 4 dice, and count only the fives and sixes; but you need to get a total count of 4, you have a 1.23% chance; if then you had the choice of rolling one more dice under the same terms, how does that effect teh whole
<Greys>
kspacademia is not a place I can be
<Greys>
I tried, not gonna work
<Greys>
without consideration for the logic, it should look like this, but I think it becomes a montian hallway http://anydice.com/program/e23e
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<UmbralRaptor>
greys: treat as a binomial distributed with a probability of success of 1/3, and plug in 4 and 5 successes for 5 trials?